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27/125=(25/9)^x-4
We move all terms to the left:
27/125-((25/9)^x-4)=0
Domain of the equation: 9)^x-4)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-((+25/9)^x-4)+27/125=0
We calculate fractions
()/9^x-4)*125)+243x/9^x-4)*125)=0
We calculate fractions
(()*9^x)/81x^2+(-4)*125)+243x*9^x)/81x^2=0
We multiply all the terms by the denominator
(()*9^x)+(-4)*125)+243x*9^x)=0
We calculate terms in parentheses: +(()*9^x), so:We get rid of parentheses
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(()*9^x)-4)*125)+243x*9^x=0
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| x^2+2x-3599=0 | | (y-1)^2=2y^2-5y-17 | | 2x-4/3-3x+2/4=x-5/6-3 | | 0=6x^2-7x-5 | | (X+104)+3x=180 | | x^2=5.5x-6 | | 1/(x^2+6x+100)=0 | | 14k-70=2(3k+5) | | 8x-25=3(2x-5) | | 8x+25=3(2x-5) | | 13k-20=2(5k+2) | | 13k-20=2(5k+20) | | 13k-44=2(4k+3) | | 9x-18=3(2x-4) | | 2+3(x+1)=5 | | 8x-10+4=10x | | 11+4(x-3)=3 | | 8x-10+4=2x | | x/10-6=5/6 | | -4x^2-4x+12=0 | | (1.8/n)=(0.7/12) | | (4+z)(3z+1)=0 | | (X+7)2+(7-x)2=130 | | 4/x+1-3-x/2=2 | | X/x+1-x+1/X=13/6 | | 2(5−8k)−13=9(1−k)−12 | | 4t=60/10t | | 500=10+7n-7 | | 1/5(x-4)=2x/3 | | x^2+138x-4761=0 | | 0=-0.07x^2+x+2.2 | | -32-17-2z=-3 |